Pretty simple case actually. I'm assuming you mean a basic six-sided die.
1/6 * 1/2 * 1/2 = 1/24 or 4.17%.
Since each event is independent, you multiply the probabilities of each.
I think 1/12 is right because you still have a 50% probability of getting heads on both. You still have a 2 out of 4 chance on the quarters which reduces to 1/2.
You don't have a 2/4 chance on the quarters. The possibilities are HT HH TH TT, so HH is 1/4.
Unless, they are counting the three possibilities as two heads, two tails, and one head/one tail. (Bogus, but whatever.) That would make it 1/3 * 1/6 = 1/18 or 5.56%. Is that one of the choices?
Yeah, it depends on whether order matters or not and that wasn't made clear. I think the crux is whether they are counting HT the same as TH (combination) or HT as different from TH (permutation).
Yeah, it depends on whether order matters or not and that wasn't made clear. I think the crux is whether they are counting HT the same as TH (combination) or HT as different from TH (permutation).
Unless, they are counting the three possibilities as two heads, two tails, and one head/one tail. (Bogus, but whatever.) That would make it 1/3 * 1/6 = 1/18 or 5.56%. Is that one of the choices?